3.113 \(\int \frac {x^4}{\sin ^{-1}(a x)^{7/2}} \, dx\)

Optimal. Leaf size=264 \[ \frac {\sqrt {2 \pi } S\left (\sqrt {\frac {2}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{15 a^5}+\frac {8 \sqrt {6 \pi } S\left (\sqrt {\frac {6}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{5 a^5}-\frac {5 \sqrt {\frac {3 \pi }{2}} S\left (\sqrt {\frac {6}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{a^5}+\frac {5 \sqrt {\frac {5 \pi }{2}} S\left (\sqrt {\frac {10}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{3 a^5}-\frac {16 x^3}{15 a^2 \sin ^{-1}(a x)^{3/2}}+\frac {40 x^4 \sqrt {1-a^2 x^2}}{3 a \sqrt {\sin ^{-1}(a x)}}-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}-\frac {32 x^2 \sqrt {1-a^2 x^2}}{5 a^3 \sqrt {\sin ^{-1}(a x)}}+\frac {4 x^5}{3 \sin ^{-1}(a x)^{3/2}} \]

[Out]

-16/15*x^3/a^2/arcsin(a*x)^(3/2)+4/3*x^5/arcsin(a*x)^(3/2)-9/10*FresnelS(6^(1/2)/Pi^(1/2)*arcsin(a*x)^(1/2))*6
^(1/2)*Pi^(1/2)/a^5+1/15*FresnelS(2^(1/2)/Pi^(1/2)*arcsin(a*x)^(1/2))*2^(1/2)*Pi^(1/2)/a^5+5/6*FresnelS(10^(1/
2)/Pi^(1/2)*arcsin(a*x)^(1/2))*10^(1/2)*Pi^(1/2)/a^5-2/5*x^4*(-a^2*x^2+1)^(1/2)/a/arcsin(a*x)^(5/2)-32/5*x^2*(
-a^2*x^2+1)^(1/2)/a^3/arcsin(a*x)^(1/2)+40/3*x^4*(-a^2*x^2+1)^(1/2)/a/arcsin(a*x)^(1/2)

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Rubi [A]  time = 0.40, antiderivative size = 264, normalized size of antiderivative = 1.00, number of steps used = 17, number of rules used = 5, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {4633, 4719, 4631, 3305, 3351} \[ \frac {\sqrt {2 \pi } S\left (\sqrt {\frac {2}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{15 a^5}+\frac {8 \sqrt {6 \pi } S\left (\sqrt {\frac {6}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{5 a^5}-\frac {5 \sqrt {\frac {3 \pi }{2}} S\left (\sqrt {\frac {6}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{a^5}+\frac {5 \sqrt {\frac {5 \pi }{2}} S\left (\sqrt {\frac {10}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{3 a^5}+\frac {40 x^4 \sqrt {1-a^2 x^2}}{3 a \sqrt {\sin ^{-1}(a x)}}-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}-\frac {16 x^3}{15 a^2 \sin ^{-1}(a x)^{3/2}}-\frac {32 x^2 \sqrt {1-a^2 x^2}}{5 a^3 \sqrt {\sin ^{-1}(a x)}}+\frac {4 x^5}{3 \sin ^{-1}(a x)^{3/2}} \]

Antiderivative was successfully verified.

[In]

Int[x^4/ArcSin[a*x]^(7/2),x]

[Out]

(-2*x^4*Sqrt[1 - a^2*x^2])/(5*a*ArcSin[a*x]^(5/2)) - (16*x^3)/(15*a^2*ArcSin[a*x]^(3/2)) + (4*x^5)/(3*ArcSin[a
*x]^(3/2)) - (32*x^2*Sqrt[1 - a^2*x^2])/(5*a^3*Sqrt[ArcSin[a*x]]) + (40*x^4*Sqrt[1 - a^2*x^2])/(3*a*Sqrt[ArcSi
n[a*x]]) + (Sqrt[2*Pi]*FresnelS[Sqrt[2/Pi]*Sqrt[ArcSin[a*x]]])/(15*a^5) - (5*Sqrt[(3*Pi)/2]*FresnelS[Sqrt[6/Pi
]*Sqrt[ArcSin[a*x]]])/a^5 + (8*Sqrt[6*Pi]*FresnelS[Sqrt[6/Pi]*Sqrt[ArcSin[a*x]]])/(5*a^5) + (5*Sqrt[(5*Pi)/2]*
FresnelS[Sqrt[10/Pi]*Sqrt[ArcSin[a*x]]])/(3*a^5)

Rule 3305

Int[sin[(e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Sin[(f*x^2)/d], x], x,
Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3351

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 4631

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^m*Sqrt[1 - c^2*x^2]*(a + b*ArcSin
[c*x])^(n + 1))/(b*c*(n + 1)), x] - Dist[1/(b*c^(m + 1)*(n + 1)), Subst[Int[ExpandTrigReduce[(a + b*x)^(n + 1)
, Sin[x]^(m - 1)*(m - (m + 1)*Sin[x]^2), x], x], x, ArcSin[c*x]], x] /; FreeQ[{a, b, c}, x] && IGtQ[m, 0] && G
eQ[n, -2] && LtQ[n, -1]

Rule 4633

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^m*Sqrt[1 - c^2*x^2]*(a + b*ArcSin
[c*x])^(n + 1))/(b*c*(n + 1)), x] + (Dist[(c*(m + 1))/(b*(n + 1)), Int[(x^(m + 1)*(a + b*ArcSin[c*x])^(n + 1))
/Sqrt[1 - c^2*x^2], x], x] - Dist[m/(b*c*(n + 1)), Int[(x^(m - 1)*(a + b*ArcSin[c*x])^(n + 1))/Sqrt[1 - c^2*x^
2], x], x]) /; FreeQ[{a, b, c}, x] && IGtQ[m, 0] && LtQ[n, -2]

Rule 4719

Int[(((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*((f_.)*(x_))^(m_.))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[
((f*x)^m*(a + b*ArcSin[c*x])^(n + 1))/(b*c*Sqrt[d]*(n + 1)), x] - Dist[(f*m)/(b*c*Sqrt[d]*(n + 1)), Int[(f*x)^
(m - 1)*(a + b*ArcSin[c*x])^(n + 1), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[c^2*d + e, 0] && LtQ[n,
-1] && GtQ[d, 0]

Rubi steps

\begin {align*} \int \frac {x^4}{\sin ^{-1}(a x)^{7/2}} \, dx &=-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}+\frac {8 \int \frac {x^3}{\sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{5/2}} \, dx}{5 a}-(2 a) \int \frac {x^5}{\sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{5/2}} \, dx\\ &=-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}-\frac {16 x^3}{15 a^2 \sin ^{-1}(a x)^{3/2}}+\frac {4 x^5}{3 \sin ^{-1}(a x)^{3/2}}-\frac {20}{3} \int \frac {x^4}{\sin ^{-1}(a x)^{3/2}} \, dx+\frac {16 \int \frac {x^2}{\sin ^{-1}(a x)^{3/2}} \, dx}{5 a^2}\\ &=-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}-\frac {16 x^3}{15 a^2 \sin ^{-1}(a x)^{3/2}}+\frac {4 x^5}{3 \sin ^{-1}(a x)^{3/2}}-\frac {32 x^2 \sqrt {1-a^2 x^2}}{5 a^3 \sqrt {\sin ^{-1}(a x)}}+\frac {40 x^4 \sqrt {1-a^2 x^2}}{3 a \sqrt {\sin ^{-1}(a x)}}+\frac {32 \operatorname {Subst}\left (\int \left (-\frac {\sin (x)}{4 \sqrt {x}}+\frac {3 \sin (3 x)}{4 \sqrt {x}}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{5 a^5}-\frac {40 \operatorname {Subst}\left (\int \left (-\frac {\sin (x)}{8 \sqrt {x}}+\frac {9 \sin (3 x)}{16 \sqrt {x}}-\frac {5 \sin (5 x)}{16 \sqrt {x}}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{3 a^5}\\ &=-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}-\frac {16 x^3}{15 a^2 \sin ^{-1}(a x)^{3/2}}+\frac {4 x^5}{3 \sin ^{-1}(a x)^{3/2}}-\frac {32 x^2 \sqrt {1-a^2 x^2}}{5 a^3 \sqrt {\sin ^{-1}(a x)}}+\frac {40 x^4 \sqrt {1-a^2 x^2}}{3 a \sqrt {\sin ^{-1}(a x)}}-\frac {8 \operatorname {Subst}\left (\int \frac {\sin (x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{5 a^5}+\frac {5 \operatorname {Subst}\left (\int \frac {\sin (x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{3 a^5}+\frac {25 \operatorname {Subst}\left (\int \frac {\sin (5 x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{6 a^5}+\frac {24 \operatorname {Subst}\left (\int \frac {\sin (3 x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{5 a^5}-\frac {15 \operatorname {Subst}\left (\int \frac {\sin (3 x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{2 a^5}\\ &=-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}-\frac {16 x^3}{15 a^2 \sin ^{-1}(a x)^{3/2}}+\frac {4 x^5}{3 \sin ^{-1}(a x)^{3/2}}-\frac {32 x^2 \sqrt {1-a^2 x^2}}{5 a^3 \sqrt {\sin ^{-1}(a x)}}+\frac {40 x^4 \sqrt {1-a^2 x^2}}{3 a \sqrt {\sin ^{-1}(a x)}}-\frac {16 \operatorname {Subst}\left (\int \sin \left (x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{5 a^5}+\frac {10 \operatorname {Subst}\left (\int \sin \left (x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{3 a^5}+\frac {25 \operatorname {Subst}\left (\int \sin \left (5 x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{3 a^5}+\frac {48 \operatorname {Subst}\left (\int \sin \left (3 x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{5 a^5}-\frac {15 \operatorname {Subst}\left (\int \sin \left (3 x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{a^5}\\ &=-\frac {2 x^4 \sqrt {1-a^2 x^2}}{5 a \sin ^{-1}(a x)^{5/2}}-\frac {16 x^3}{15 a^2 \sin ^{-1}(a x)^{3/2}}+\frac {4 x^5}{3 \sin ^{-1}(a x)^{3/2}}-\frac {32 x^2 \sqrt {1-a^2 x^2}}{5 a^3 \sqrt {\sin ^{-1}(a x)}}+\frac {40 x^4 \sqrt {1-a^2 x^2}}{3 a \sqrt {\sin ^{-1}(a x)}}+\frac {\sqrt {2 \pi } S\left (\sqrt {\frac {2}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{15 a^5}-\frac {5 \sqrt {\frac {3 \pi }{2}} S\left (\sqrt {\frac {6}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{a^5}+\frac {8 \sqrt {6 \pi } S\left (\sqrt {\frac {6}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{5 a^5}+\frac {5 \sqrt {\frac {5 \pi }{2}} S\left (\sqrt {\frac {10}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{3 a^5}\\ \end {align*}

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Mathematica [C]  time = 0.74, size = 417, normalized size = 1.58 \[ \frac {9 e^{3 i \sin ^{-1}(a x)} \left (-12 \sin ^{-1}(a x)^2+2 i \sin ^{-1}(a x)+1\right )+2 e^{i \sin ^{-1}(a x)} \left (4 \sin ^{-1}(a x)^2-2 i \sin ^{-1}(a x)-3\right )+e^{5 i \sin ^{-1}(a x)} \left (100 \sin ^{-1}(a x)^2-10 i \sin ^{-1}(a x)-3\right )-8 \sqrt {-i \sin ^{-1}(a x)} \sin ^{-1}(a x)^2 \Gamma \left (\frac {1}{2},-i \sin ^{-1}(a x)\right )+108 \sqrt {3} \sqrt {-i \sin ^{-1}(a x)} \sin ^{-1}(a x)^2 \Gamma \left (\frac {1}{2},-3 i \sin ^{-1}(a x)\right )-100 \sqrt {5} \sqrt {-i \sin ^{-1}(a x)} \sin ^{-1}(a x)^2 \Gamma \left (\frac {1}{2},-5 i \sin ^{-1}(a x)\right )+e^{-i \sin ^{-1}(a x)} \left (8 \sin ^{-1}(a x)^2+4 i \sin ^{-1}(a x)+8 e^{i \sin ^{-1}(a x)} \left (i \sin ^{-1}(a x)\right )^{5/2} \Gamma \left (\frac {1}{2},i \sin ^{-1}(a x)\right )-6\right )-9 e^{-3 i \sin ^{-1}(a x)} \left (12 \sin ^{-1}(a x)^2+2 i \sin ^{-1}(a x)+12 \sqrt {3} e^{3 i \sin ^{-1}(a x)} \left (i \sin ^{-1}(a x)\right )^{5/2} \Gamma \left (\frac {1}{2},3 i \sin ^{-1}(a x)\right )-1\right )+e^{-5 i \sin ^{-1}(a x)} \left (100 \sin ^{-1}(a x)^2+10 i \sin ^{-1}(a x)+100 \sqrt {5} e^{5 i \sin ^{-1}(a x)} \left (i \sin ^{-1}(a x)\right )^{5/2} \Gamma \left (\frac {1}{2},5 i \sin ^{-1}(a x)\right )-3\right )}{240 a^5 \sin ^{-1}(a x)^{5/2}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[x^4/ArcSin[a*x]^(7/2),x]

[Out]

(9*E^((3*I)*ArcSin[a*x])*(1 + (2*I)*ArcSin[a*x] - 12*ArcSin[a*x]^2) + 2*E^(I*ArcSin[a*x])*(-3 - (2*I)*ArcSin[a
*x] + 4*ArcSin[a*x]^2) + E^((5*I)*ArcSin[a*x])*(-3 - (10*I)*ArcSin[a*x] + 100*ArcSin[a*x]^2) - 8*Sqrt[(-I)*Arc
Sin[a*x]]*ArcSin[a*x]^2*Gamma[1/2, (-I)*ArcSin[a*x]] + (-6 + (4*I)*ArcSin[a*x] + 8*ArcSin[a*x]^2 + 8*E^(I*ArcS
in[a*x])*(I*ArcSin[a*x])^(5/2)*Gamma[1/2, I*ArcSin[a*x]])/E^(I*ArcSin[a*x]) + 108*Sqrt[3]*Sqrt[(-I)*ArcSin[a*x
]]*ArcSin[a*x]^2*Gamma[1/2, (-3*I)*ArcSin[a*x]] - (9*(-1 + (2*I)*ArcSin[a*x] + 12*ArcSin[a*x]^2 + 12*Sqrt[3]*E
^((3*I)*ArcSin[a*x])*(I*ArcSin[a*x])^(5/2)*Gamma[1/2, (3*I)*ArcSin[a*x]]))/E^((3*I)*ArcSin[a*x]) - 100*Sqrt[5]
*Sqrt[(-I)*ArcSin[a*x]]*ArcSin[a*x]^2*Gamma[1/2, (-5*I)*ArcSin[a*x]] + (-3 + (10*I)*ArcSin[a*x] + 100*ArcSin[a
*x]^2 + 100*Sqrt[5]*E^((5*I)*ArcSin[a*x])*(I*ArcSin[a*x])^(5/2)*Gamma[1/2, (5*I)*ArcSin[a*x]])/E^((5*I)*ArcSin
[a*x]))/(240*a^5*ArcSin[a*x]^(5/2))

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4/arcsin(a*x)^(7/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{4}}{\arcsin \left (a x\right )^{\frac {7}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4/arcsin(a*x)^(7/2),x, algorithm="giac")

[Out]

integrate(x^4/arcsin(a*x)^(7/2), x)

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maple [A]  time = 0.13, size = 225, normalized size = 0.85 \[ -\frac {108 \sqrt {2}\, \sqrt {\pi }\, \sqrt {3}\, \mathrm {S}\left (\frac {\sqrt {2}\, \sqrt {3}\, \sqrt {\arcsin \left (a x \right )}}{\sqrt {\pi }}\right ) \arcsin \left (a x \right )^{\frac {5}{2}}-100 \sqrt {2}\, \sqrt {\pi }\, \sqrt {5}\, \mathrm {S}\left (\frac {\sqrt {2}\, \sqrt {5}\, \sqrt {\arcsin \left (a x \right )}}{\sqrt {\pi }}\right ) \arcsin \left (a x \right )^{\frac {5}{2}}-8 \sqrt {2}\, \sqrt {\pi }\, \mathrm {S}\left (\frac {\sqrt {2}\, \sqrt {\arcsin \left (a x \right )}}{\sqrt {\pi }}\right ) \arcsin \left (a x \right )^{\frac {5}{2}}-8 \arcsin \left (a x \right )^{2} \sqrt {-a^{2} x^{2}+1}+108 \arcsin \left (a x \right )^{2} \cos \left (3 \arcsin \left (a x \right )\right )-100 \arcsin \left (a x \right )^{2} \cos \left (5 \arcsin \left (a x \right )\right )-4 a x \arcsin \left (a x \right )+18 \arcsin \left (a x \right ) \sin \left (3 \arcsin \left (a x \right )\right )-10 \arcsin \left (a x \right ) \sin \left (5 \arcsin \left (a x \right )\right )+6 \sqrt {-a^{2} x^{2}+1}-9 \cos \left (3 \arcsin \left (a x \right )\right )+3 \cos \left (5 \arcsin \left (a x \right )\right )}{120 a^{5} \arcsin \left (a x \right )^{\frac {5}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4/arcsin(a*x)^(7/2),x)

[Out]

-1/120/a^5*(108*2^(1/2)*Pi^(1/2)*3^(1/2)*FresnelS(2^(1/2)/Pi^(1/2)*3^(1/2)*arcsin(a*x)^(1/2))*arcsin(a*x)^(5/2
)-100*2^(1/2)*Pi^(1/2)*5^(1/2)*FresnelS(2^(1/2)/Pi^(1/2)*5^(1/2)*arcsin(a*x)^(1/2))*arcsin(a*x)^(5/2)-8*2^(1/2
)*Pi^(1/2)*FresnelS(2^(1/2)/Pi^(1/2)*arcsin(a*x)^(1/2))*arcsin(a*x)^(5/2)-8*arcsin(a*x)^2*(-a^2*x^2+1)^(1/2)+1
08*arcsin(a*x)^2*cos(3*arcsin(a*x))-100*arcsin(a*x)^2*cos(5*arcsin(a*x))-4*a*x*arcsin(a*x)+18*arcsin(a*x)*sin(
3*arcsin(a*x))-10*arcsin(a*x)*sin(5*arcsin(a*x))+6*(-a^2*x^2+1)^(1/2)-9*cos(3*arcsin(a*x))+3*cos(5*arcsin(a*x)
))/arcsin(a*x)^(5/2)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4/arcsin(a*x)^(7/2),x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: Error executing code in Maxima: expt: undefined: 0 to a negative e
xponent.

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {x^4}{{\mathrm {asin}\left (a\,x\right )}^{7/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4/asin(a*x)^(7/2),x)

[Out]

int(x^4/asin(a*x)^(7/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{4}}{\operatorname {asin}^{\frac {7}{2}}{\left (a x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4/asin(a*x)**(7/2),x)

[Out]

Integral(x**4/asin(a*x)**(7/2), x)

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